Database Architects Salary in Florida

Database architects in Florida earn the most in Sarasota (average $156,240 a year) and the least in Tampa ($139,760), across the 6 Florida metro areas we cover. Statewide, BLS puts the database architects average at $142,270 and the median at $138,320 for 1,810 workers. The U.S. average for this job is $144,440.

Database Architects average salary by city in Florida

Sarasota$156,240
Orlando$149,480
Miami$144,750
Jacksonville$141,880
Palm Bay$141,010
Tampa$139,760

Pay, take-home pay and cost of living

City	Average	Median	25th pct.	Take-home*	Cost of living
Sarasota	$156,240	$157,730	$129,560	$118,056	102
Orlando	$149,480	$143,540	$109,830	$113,436	101
Miami	$144,750	$141,170	$118,690	$110,203	114
Jacksonville	$141,880	$136,640	$98,140	$108,241	99
Palm Bay	$141,010	$150,330	$96,400	$107,646	100
Tampa	$139,760	$133,290	$97,710	$106,792	101

*Average salary after federal and state taxes for a single filer; Florida has no state income tax. Cost of living: BEA price parity, U.S. = 100.

Database Architects salary in other states

Database Architects salary by city and state

More about pay in Florida

Sources and how to read this page

Wages: U.S. Bureau of Labor Statistics, Occupational Employment and Wage Statistics (OEWS), May 2025 estimates for metropolitan areas. SOC code 15-1243.
U.S. and statewide figures: BLS OEWS national and state estimates, May 2025, every employer including rural areas.
Cost of living: Bureau of Economic Analysis regional price parities (RPP), 2024; 100 = U.S. average.

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